Is there a mathematically or...er....programmatically? ...more efficient way to do this:

If newx > oldx + 100
;do stuff
elseIf newx < oldx - 100
;do stuff
elseIf newy > oldy + 100
;do stuff
elseIf newy < oldy - 100
;do stuff
endif


I tried this at first but then realized this was completly wrong:

If abs(newx) > oldx + 100
;do stuff
elseIf abs(newy) > oldx + 100
;do stuff
endif