I really like the hacking system in Fallout; I think it's quite elegant. I'm very curious as to whether, if you are making a correct logical choice each try, it is mathematically impossible to lock a terminal in Fallout 3 or 4.
These are my basic assumptions of the system so far.
- Each screen has ten words, in addition to a RESET TRIES and a DUD REMOVE. (not sure what percentage of the time these two appear).
- Each word is related to another word in the list by a minimum number of letters based on the length of the word (i.e. a 4 letter word will have at least 1 likeness with another 4 letter word, seven letter words will have at least 3 likenesses. I'm not 100% certain this is true, and I'd love to know the math on this.
- Each word probably has some variance calculation so that there aren't too many words in one group of likenesses, i.e. 10 'ING' words with 5 'B' prefixes and 3 shared letters in the center.
MY THEORY is that if you select a word, then select another word that has a correct number of likenesses to word 1, then select a third word that has a correct number of likenesses to word 1 and 2, it is mathematically impossible that the fourth word you select (matching all three likenesses) will be incorrect apart from human error. But I don't actually know for sure. Would a Bethesda person be willing to shed light on how this works? Has anyone else done the math?