but a nuclear exchange would destroy almost all bombers while there still on the ground, [...]
That's absolutely ludicrous. If that were remotely possible, then the United States would never have spent the
tens of trillions of dollars it did on the http://en.wikipedia.org/wiki/Strategic_Air_Command (Strategic Air Command).
Even an ICBM is nto instantaneous - the launch phase (ground to orbit) is 3 to 5 minutes, followed by a 25-minute midcourse phase, and finally, a roughly 2 minute re-entry phase. That's a total flight time of at least a half-hour - and right now, TODAY, we have the ability to detect the missiles
as they are launched. The war of Fallout's universe is set seventy years into our future; I hardly think their on-launch detection capability is any less than ours - especially given that they, unlike us, have things like man-portable directed energy weaponry, and fully-functional Artificial Intelligence ...!
And since
their Cold War either never ended, or, was restarted? Then I figure they (unlike us) would have continued to maintain and operate a http://en.wikipedia.org/wiki/Global_Strike_Command, which means there'd've been many bombers
on hot standby, fuelled and ready to take off with less than five minutes' warning. (In fact, in 2008 the Air Force created a new MAJCOM, the http://en.wikipedia.org/wiki/Global_Strike_Command, which is essentially the SAC reborn.)
[...] and EMPs would effect military aircraft, yes avionics are sheiled, but nothing can protect against gamma radiation except ridicolous amounts of lead shielding (even then some gets through)
You're combining two entirely separate effects. Yes, the EMP is produced by the gamma radiation of a nuclear detonation - because ... well, I'll just quote Wikipedia, because I can't really improve on the explaination:
Gamma rays from a nuclear explosion produce high energy electrons through Compton scattering. These electrons are captured in the earth's magnetic field, at altitudes between twenty and forty kilometers, where they resonate. The oscillating electric current produces a coherent electromagnetic pulse (EMP) which lasts about one millisecond. Secondary effects may last for more than a second.
The pulse is powerful enough to cause long metal objects (such as cables) to act as antennas and generate high voltages when the pulse passes. These voltages, and the associated high currents, can destroy unshielded electronics and even many wires. There are no known biological effects of EMP. The ionized air also disrupts radio traffic that would normally bounce off the ionosphere.
One can shield electronics by wrapping them completely in conductive mesh, or any other form of Faraday cage. Of course radios cannot operate when shielded, because broadcast radio waves cannot reach them.
Note, the EMP is not generated by the passing of Gamma rays through the electronic equipment - the EMP is produced by
a magnetic oscillation in the atmosphere 30 to 40 kilometers above the Earth. So, shielding against Gamma radiation has
nothing to do with shielding or hardening electronics to handle an EMP.
Nothing. Now, consider this: the entire aircraft is, itself, a "long metallic object" ... and the electronics, aside from radios, are entirely contained within the skin of the aircraft fuselage. A fuselage which can be struck by lightning - instantaneous voltage-spikes in the
megawatt range, if not higher - with
absolutely no effect. That is because the aircraft's skin acts as a faraday cage. For any voltage, EMP or otherwise, to get inside the aircraft and affect the electronics within, it would have to essentially
melt the airplane ... at which point, the effect on the electronics ceases to be a concern.
Furthermore, try to remember that the fallout universe still largely uses vacuum-tube based electrical systems, and:
Older, vacuum tube (valve) based equipment is much less vulnerable to EMP; Soviet Cold War–era military aircraft often had avionics based on vacuum tubes.
(http://en.wikipedia.org/wiki/Electromagnetic_pulse#Practical_considerations_for_nuclear_EMP) That means, most FO-universe electronics are far, far less vulnerable to EMP than ours are. Even the civilian stuff - like those PIP-Boy units - aren't going to be automatically fried.
And, some more from the same source:
Many nuclear detonations have taken place using bombs dropped by aircraft. The B-29 aircraft that delivered the atomic weapons at Hiroshima and Nagasaki did not lose power due to damage to their electrical or electronic systems. This is simply because electrons (ejected from the air by gamma rays) are stopped quickly in normal air for bursts below 10 km, so they do not get a chance to be significantly deflected by the Earth's magnetic field (the deflection causes the powerful EMP seen in high altitude bursts), but it does point out the limited use of smaller burst altitudes for widespread EMP.
So, all those explosions down near the ground? The ones actually destroying cities?
Aren't producing large EMPs, certainly not large enough to penetrate the natural faraday cage of a modern, metal-skinned aircraft! (There
is another sort of EMP - direct http://en.wikipedia.org/wiki/Photoinduced_charge_separation, or "radial EMP"; however, for those sub-10km-altitude detonations, this only occurs in the "intense" nuclear radiation zone, at which point, the primary
blast effects are more likely to be an immediate concern than radiation or EMP.)
As for direct exposure to Gamma radiation? That won't kill the crew of an aircraft instantly. Indeed, to be subject to lethal radiation, even from a 20-megaton device ... the best number I can come up with, for a lethal dose of radiation is that you'd have to be, on average, within 5 kilometers of the actual epicenter of the blast itself. At which point, for an aircraft? You just got turned into a few hundred pieces of metallic debris, and radiation is the
last of yoru worries.
...
IN SUMMARY: The bombers would NOT all have been destroyed on the ground. Given any at-launch detection capability at all, there would be a solid twenty-minute-or-more window in which those bombers could be scrambled and put in the air.
Those that were in the air would NOT all have been eliminated by EMP, in part because they would not all have been subjected to a primary EMP detonation (Militaries like to coordinate things like "we're going to hit 'em with some EMPs, and we're sendign in bombers - let's make sure the bombers don't get EMPed too!"). And, in part, because even if they WERE, their systems are protected by a multi-ton faraday cage, called "the aircraft itself". And, finally, because they are vacuum-tube-based systems, and as such
inherently less vulnerable to EMP damage.
...
It kind of pays to have a basic, working understanding of how these things
really work, rather than relying on Hollywood-spawned nonsense, before you make absolutist statements like your claims RE: bombers in a nuclear war.
EDIT TO ADD:
Not to come across like an ass... but I was a Missile Launch Officer for eight years, I do have a rough idea how this works. We would be using ALL legs of the nuclear triad. The bombs would not be stopping after a mere two hours.
Honestly, I presume that the two-hour span mentioned was the time from the first major detonation, until the final major detonation - counting only strategic-scale weapons. Any tactical- or sub-strategic detonations, at THAT point, are so far beyond even overkill, as to simply not matter.
IOW: two hours of
city-killers actually going "boom". Two hours of mushroom clouds far far
larger than Megaton's blast, in every direction. *yipe!*
And, on that side-note: Megaton's bomb was a
wee little smallfry, yield-wise - just look at how short that mushroom cloud was! Seriously, I'd estimate that as a sub-100kT device. Possibly, sub-20kT, even. I doubt the cloud topped 20,000' in height, and it certainly wasn't over 40,000'.